From here it’s mathematical in calculating what the young will look like. If a snake possesses two dominant genes for a dark color (called homozygous for that color trait), then all the offspring will have that dark color, no matter what color the other parent snake was because all of the offspring would have at least one of the dominant genes (heterozygous for the color trait) from the homozygous dark parent. If the dark parent had one dominant gene for the dark color and one recessive gene for no dark color, then the color of the babies would depend on the other parent. If the other parent were homozygous for dark color, then all young would be dark because of what I said above, they would all have at least one of the dark color genes (actually 50% of the young would be homozygous for the dark gene and 50% would be heterozygous for the dark gene). If both parent were heterozygous for the dark gene (or in other words each had one gene for the dark color and one for the absence of the dark color), then 75% of the young would be dark in color (25% would be homozygous for the dark gene and 50% heterozygous for the dark gene) and 25% would be light in color (or homozygous for the absence of the dark gene.

Sounds confusing and like gobbly gook doesn’t it. It takes a little bit of education to learn how genes work and combine to create the color morphs we see out there.